§1. General presentation
§1.1. Tablet YBC 4698 provides an interesting overview of the mathematical approach to economic problems in the Old Babylonian period. Although well preserved (see the photo posted at /P255010), the text has been poorly published. In MKT 1, Neugebauer confessed that he was not able to publish the text.^{[2]} In MKT 3, he made little progress. He transliterated the text leaving many signs unidentified, and translated only a small portion of it (MKT 3, 4245). Neugebauer recognized that his difficulties came mainly from the fact that he was not familiar with economic terminology.^{[3]} ThureauDangin improved the reading of some words, and provided a transcription and translation of section 16, the rest of the text remaining quite obscure (ThureauDangin 1937b, 8990). In TMB, he only quoted the text (p. 214) and referred to MKT 3 and to his previous paper.^{[4]} Friberg, in different chapters of his 2005 monograph (2005: 23 n. 10, 6061, 6768, and 215218), made substantive improvements to YBC 4698’s reading and translations, as well as interpretation of problems 3, 6, 7, 8, 9 and 10. However, he considered the problems as isolated entities. In this article, we try to look at the text as a whole, and to understand how the different problems are interconnected.
§1.2. Few mathematical texts dealing with economic matters are known to date. As noted by Neugebauer and Sachs (1945: 106), “the published mathematical texts concerning prices are badly preserved or obscure for other reasons.” Among these economic mathematical texts are VAT 7530, MLC 1842,^{[5]} as well as some texts discovered after the publication of MKT and MCT, such as texts from Susa (TMS 13 and 22^{[6]}), from the Diyala Valley (IM 54464),^{[7]} and from southern Mesopotamia (MS 3895).^{[8]} Nowadays, the reading and interpretation of YBC 4698 can be improved as we profit from a larger comparative material, from a better understanding of economic texts and mathematical series texts, and from Friberg’s work on “combined market rate exercises” (Friberg 2007: 157168). Thus, in this article we can provide an almost complete transliteration, translation and possible interpretations of the preserved portions of the text.
§1.3. The type of tablet is M(2,2) (multicolumn tablet, with 2 columns on the obverse and 2 columns on the reverse). The text contains 17 problem statements on interest rates, prices and profit, and ends with a colophon which indicates that the tablet is the third of a series (dub 3kamma). Thus, YBC 4698 belongs to the small collection of 20 mathematical series tablets known to date. The origin of this tablet is unknown. However, the series tablets probably date from the end of the Old Babylonian period (late 18^{th} century or early 17^{th}), and may come from central Mesopotamia (perhaps Sippar or Kish). (See discussion on date and provenience of mathematical series tablets and related bibliography in Proust 2009b: 169170.)
§1.4. Although damaged, one guesses that the colophon contained the number of sections (17 imšu) as well, though this reference seems to have been erased in antiquity. Each of the 17 sections contains the statement of a problem, without any indication about the procedure of resolution. All of the statements deal with the same general topic, namely economic issues. The writing uses mainly sumerograms, but it is not clear if the text is written in Akkadian, in Sumerian, or in a completely artificial language (see discussion in Proust 2009b: 170171).
§1.5 The list of 17 problem statements found in YBC 4698 can be divided into several homogeneous groups (for more details, see §6):
#12: The interest is given, find the principal.
#35: The rate inkind or values of two kinds of goods are different; find the price of each of them in various conditions.
#611: The purchase price and the selling price of a good are given; find the profit (and reciprocal problems).
#1214: similar to #35, but the resolution of the problem involves division by nonregular numbers.
#1516: Different ratios are used to evaluate goods. Find the values or rates.
#17: Rates are used to evaluate value of two kinds of stones. Find the weight of the stones.
§2. Terminology
A glossary is provided in §8. Here, we emphasize the technical meaning of expressions used in economic problems.
§2.1. The suffix –ta. As an economic mathematical text, YBC 4698 exhibits some features and terminology similar to those found in economic archives. For instance, the ablative suffix –ta is used to indicate rate per unit. The same layout is described by Snell (1982, 39) for Ur III documents. According to Snell (ibid., 116), the silver implied with this formula is 1 gin_{2}. This rendered the market rate, x unit quantity per 1 gin_{2} of silver (example: “9 sila_{3}ta” means “9 sila_{3} per (gin_{2} of silver).” This is seen here where the silver given (written ‘sum’) in problems 3, 11 – 13 and probably 9 is stated as 1 gin_{2} of silver per unit, as well as problems 58, 10, and probably 1517, where 1 gin_{2} given per unit is implied. Only problem 14, a combined market rate exercise where the market rate is stipulated, differs from this formula (see §6.14). When identified as a rate per unit, we translate the suffix –ta as “per unit”; this unit is generally 1 gin_{2}, thus, we can often translate as “per gin_{2}.”
§2.2. sa_{10}. ‘sa_{10}’ is an interesting verb in these texts, and its exact understanding is essential for the interpretation of the problems. Neugebauer and Sachs first suggested the basic meaning of this verb as “to be equivalent,” with the nominalized form “equivalent” (written ‘šam_{2}’ in MCT 97). This is taken up by Jacobsen who further illustrates its use in Sumerian texts and suggests a factitive meaning “to make equivalent.” ( Jacobsen 1946: 18). The use and development of sa_{10} is elaborated further in Steinkeller 1989: 153162. When sa_{10} was used, a procedure was implied, namely, making the equivalence of one item, expressed as a quantity in a standard metrological system, to another item, expressed as a quantity in another standard metrological system. One literally made the equivalent. In the example of YBC 4607 (problems dealing with the volume of bricks) discussed by Neugebauer and Sachs in MCT p. 97, “i_{3} šam_{2} saḫarbi,” is translated “oil, the (capacity) equivalent of its (i.e. the brick’s) volume.” The reading sa_{10} rather than the conventional šam_{2} is consistent with Steinkeller’s interpretation (1989: 155). The translation would be then “the equivalent volume,” which makes sense in the context of the calculation of brick volumes, a context where oil is somehow incongruous (see Proust 2007: 214, and Friberg 2011: 262). In YBC 4698 problem 6 we see the operation of making equivalent played out with 30 gur of grain. The rate of equivalence is specified as (1 gin_{2} silver) per 1 gur grain.
The nuance, “to make equivalent” fits well with many of sa_{10}’s appearances in YBC 4698. However, a sale of one good for a price in silver is, indeed, implied in the texts as well. Most striking in this regard is problem 6, just mentioned, which employs this verb together with the verb bur_{2} (see §2.3.) to mark a purchase and a sale respectively using silver as the medium of exchange. Moreover, problem 6 requests that one compute the gain in silver of the second transaction (represented by bur_{2}). We see then, after the first use of sa_{10}, the actor in the problem gains the right to sell the property acquired at a higher price and a payment is made in both transactions with a single medium of exchange: silver.
MerriamWebster’s translates “buy” as: “1: to acquire possession, ownership, or rights to the use or services of by payment especially of money” and “4: to be the purchasing equivalent of.” Both uses of the term “to buy” are relevant here for sa_{10}. As just seen, the acquisition of ownership, possession, and rights is certainly implied, and silver is used as the purchasing equivalent. This nuance of sa_{10} as “to buy” is supported by the Akkadian understanding of a purchase (Steinkeller 1989: 156157) which the author of YBC 4698, as an Akkadian speaker, would most certainly have been aware of. We thus retain the use of “to buy” for sa_{10} in our translation, while making full note of the understanding “to make equivalent” for this verb.
§2.3. bur_{2}. In problems #611 the verb bur_{2} is used opposite sa_{10} to denote the (re)sale of a specified product. The verb bur_{2}, equated in the lexical tradition with the Akkadian verb pašāru has several different uses assigned to it often based on context (see, for instance, Sb Voc. II 170 presented in MSL 3, 142: buur : bur_{2} = paša_{2}ru ). In mathematical texts, the Akkadian verb pašārum can take on two different meanings: “to solve” (see Friberg 2007, 296: MS 3049 #1, line 9 where pašar is tentatively translated “solve”) or “to sell.”^{[9]} The meaning to sell is played out in TMS 13: 4 where we read kî maṣi ašām u_{3} kî maṣi apšuur_{2}, “at what price did I buy and at what price did I sell?” (see §6.9. below) pašāru is used to mark the (re)sale of the purchase marked by šâmum, the Akkadian equivalent of sa_{10} (see §2.2. above). We see a similar use of pašārum in TMS 13: 12 and perhaps 15; MLC 1842: 7; VAT 6469 i: 5; VAT 6546 ii: 7; and MS 3895 (Friberg 2010: 149). What we do not see, however, is the use of the Sumerian verb bur_{2} in any of these examples. Moreover, we are not aware of any instance where bur_{2} is employed in an economic or administrative text from the Old Babylonian period. Indeed, it seems to be an academic and literary term.
§2.4. ganba. This term corresponds to the Akkadian maḫīrum for which the CAD translates as “3. tariff, price equivalent, rate” (M1, 92, 9497, especially 9697 3f ). In mathematical texts, the ‘ganba’ of a given good is either the quantity of a good equivalent to 1 gin_{2} of silver (rate inkind), or the equivalent in silver of 1 unit of a good (rate insilver). The ganba is a key concept in economic mathematical texts.^{[10]} Its translation as “market price” in mathematical texts is quite confusing for our purposes as it is actually an equivalency rate. We prefer to translate ‘ganba’ as “rate (inkind)” or “rate (insilver)” according to the context. Note that in #1415, the value is estimated ingrain instead of insilver.
We see this use born out in economic texts from the Old Babylonian period. For instance, a rate inkind appears in HE 111 (RA 15, 191: 1618) (among others) dated to the fifth year of Samsuiluna of Babylon:
2(aš) sum^{sar} šumsikillum^{sar} zaḫadin

2 gur garlic, š.plant, z.plant,

ganba 3(barig)ta

rate (inkind) 3 barig per (gin_{2} silver),

ku_{3}bi 3 ^{1}/_{3} ˹gin_{2}˺

its silver value: 3 ^{1}/_{3} gin_{2}

Moreover, a rate insilver is clear in YOS 14, 290: 13 (NBC 8014) dated to Samsuiluna year 6, where we read:
˹^{1}/_{2}˺ mana 6 ^{1}/_{2} gin_{2} ku_{3}babbar

^{1}/_{2} mana 6 ^{1}/_{2} gin_{2} silver,

sa_{10} 3 ^{2}/_{3} gin_{2} ku_{3}sig_{17}

equivalent of 3 ^{2}/_{3} gin_{2} gold,

ganbaa 10 gin_{2}taam_{3}

rate in silver 10 gin_{2} per (gin_{2} gold)

In both examples we note ganba’s appearance with the ta (am_{3}) suffix to denote an equivalency rate.
§2.5. ib_{2}sa_{2}. This verb corresponds to the Akkadian maḫārum, to make equal (see VAT 7530, obv. 10 and rev. 6). The procedure of making the quantities of various goods of different value (for example fine oil and common oil, iron and gold) equal is the basis of problems 35 and 1214 of YBC 4698, as well as most other mathematical economic problems.
§2.6. e_{3} and e_{11}. The expression “še ḫe_{2}e_{3} u_{3} ḫe_{2}e_{11}ma ganba ib_{2}sa_{2},” “let the grain rise and fall so that the rates are equal,” found in #14, is the exact parallel of the Akkadian expression “ku_{3}babbar lili liriidma ganba liimtaahra” found in VAT 7530, 1920. A variant of the same expression appears as well in #15 (§6 below). This reading, which improves the understanding of the three last problems of the tablet, was suggested to us by Antoine Cavigneaux (personal communication).
§2.7. ana. The term ‘ana’ may be understood either as the Akkadian ana (“to” or “for”), or Sumerian ‘ana’ (corresponding to the Akkadian word mala and translated “as much as” or “as”). In the context of series texts, the second meaning is probable. Moreover, in our text, ‘ana’ seems to connect two equivalent elements. For these reasons, we translate ‘ana’ from Sumerian, following ThureauDangin,^{[11]} although Akkadian ana cannot be excluded. However, note the use of mala in #16.
§2.8. Verbal forms. Here, as is often the case in mathematical series texts, verbal roots do not bear any grammatical element. This could lead one to leave the verbs unconjugated in the translation (as did Neugebauer in 1935; see MKT ch. 7 and Friberg 2005: 60). However, the alternation of conjugated and unconjugated Sumerian forms in series texts suggests that unconjugated roots may be abbreviations (see for example the case of AO 9072, analyzed in Proust 2009b: 171172). Moreover, in the OldBabylonian mathematical texts, generally written in Akkadian, the statements are almost always expressed in the first person singular simple past. Respecting the uses in OldBabylonian mathematical tradition, we decided to translate the verbal forms in first person preterit, as did ThureauDangin (see for example TMB 148ff.), as well as Neugebauer from 1945 (see for example MCT 112ff.).
§2.9. Translation of units of measurement. In mathematical texts, the notations of units of measurement are highly standardized, and almost always appear as Sumerian ideograms (a few exceptions are found in texts from Diyala Valley). In modern publications, some of these units are translated (e. g. še is translated in English by grain, gin_{2} by shekel, mana by mina), while others are not (e. g. sila_{3}, gur). This raises three problems. The first is consistency: if some of the units’ name cannot be translated, it is better to translate none of them. The second is the representation of ancient standardization: when units are translated in different modern languages (e. g. shekel in English, sicle in French), we artificially replace a unified ancient system by our Babel of language. The third and more important is the meaning of the modern translations: shekel is a unit of weight; however, in ancient texts, gin_{2} may represent not only a unit of weight (the sixties of one mana), but also a unit of capacities (the sixties of one sila_{3}), or surface (the sixties of one sar). Thus, following Neugebauer and Sachs in MCT, we decided to leave the Sumerian names of the units untranslated.
§3. Methodological remarks
§3.1. Our text contains only statements of problems, without procedure for resolution, and, often, with neither question nor answer. Thus, the goal of the problems is not always explicit. However, the full understanding of the statement requires the reader to solve the supposed problem. As much as possible, we tried to implement calculations leading to the solution. This raises a methodological issue: what is the historical relevance of calculations for which we have little trace in our text? This question refers to a symmetrical one: in the corpus of mathematical cuneiform texts, we find a lot of school exercises with numerical calculations, but without indication of their goal. These exercises probably correspond to statements of problems which are absent from the text. Thus, we have on the one hand, statements without resolution in series texts, and on the other hand, resolutions without statements in some school texts. Of course it would be highly speculative to decide that some of the school exercises correspond to the resolution of some of the statements found in series texts. Even so in some cases, given the similarities of numerical data, we may be tempted to do so. The important point for us is that some school exercises present a specific pattern offering a powerful tool for solving mathematical economic problems. This pattern uses a tabular format to represent the algorithm for making equivalences of values, with fixed sequences of operations represented by columns.
Col.

I

II

III

IV


Reciprocal of I

II × 28.48

I × III


Rate inkind

Rate insilver

Value insilver

Value inkind

Good 1

1

1

28.48

28.48

Good 2

2

30

14.24

28.48

Good 3

3

20

9.36

28.48

Good 4

4

15

7.12

28.48


Total


2.5

1


Table 1: tabular presentation of exchange problems based on data of MS 2830

§3.2. Interesting examples of such “combined market rate exercises” were analyzed by Friberg (2007: 157168). Eight of such exercises noted on “square tablets,” kept at Yale University, were published in MCT 17, and gathered again by K. NemetNejet (2002: 253258) with photos.^{[12]} These “combined market rate exercises” were not necessarily produced in the same mathematical context as series texts. However, they offer a relevant framework of calculation for solving most of the problems of YBC 4698. Thus, instead of implementing calculations and reasonings based on modern algebraic or arithmetic methods, we try to solve problems of our tablet by using the tabular presentation, attested in related school texts. The striking parallel between YBC 4698 and “combined market rate exercises” was first underlined by Friberg (2005: 6061). However, Friberg does not utilize this parallel to implement his own calculation. This entails a different approach for interpretation. For example, the interpretation of problems 3 and 610 by Friberg is mathematically equivalent to ours, but the manner in which the calculations are explained is not the same.
§3.3. The examples provided by Friberg are purely numerical texts, without any word indicating the context, except MS 2830, which states the total value in silver by mention of “1 gin_{2} ku_{3}babbar” (1 gin_{2} of silver) on the bottom edge.^{[13]} The first section of the reverse of MS 2830 reads as follows:
1 gin_{2} ku_{3}babbar

1

1

28.48

28.48

2

30

14.24

28.48

3

20

9.36

28.48

4

15

7.12

28.48

The relationships between data of the four columns are the following:
Column II contains the reciprocals of column I.
Column III contains the product of the values of column II by a constant coefficient (here 28.48).
Column IV contains the product of values of column I by the values of column III (that is, the coefficients of column II; thus, these products are equal).
The total of values of column III is 1, that is the number in sexagesimal place value notation corresponding, in metrological tables (see outline in §8.3), to the value “1 gin_{2} of silver” noted on the bottom edge.
Diverse mathematical situations may be represented by these relationships. The observation of interest for us is that these situations are described in many sections of the tablet YBC 4698.
§3.4. According to various parallels presented by Friberg, including YBC 4698, the meaning of the rows and the columns of the first section of the reverse of MS 2830 may be the following:
Each row corresponds to a given good (named as good 1, good 2, etc. in Table 1).
Column I contains the rate inkind of the goods, that is, the quantity equivalent to 1 gin_{2} of silver.
Column II contains the reciprocal of rates inkind, that is, the rate insilver of the goods, or, in other terms, the value in silver of 1 unit (generally, 1 sila_{3}) of the goods.
Column III contains the value in silver of the actual quantity of the goods (of which the total is usually 1 gin_{2}).
Column IV contains the actual quantities of the several goods which have been made equal.
Moreover, an important feature of the table is that the values provided in each cell are expressed in sexagesimal place value notations (henceforth SPVN).
§3.5. It is important for the following calculations to note that the relationships between columns are not always transmissible to sums and differences: they are for multiplication by a coefficient (for example, items of column III are the products of items of column II by a coefficient, and it is the same for the sum), and are not for reciprocals and products of columns (for example, items of column II are the reciprocals of items of column I, but the sum of column II is not the reciprocal of the sum of column I).
§3.6. Many of the problems of our tablet are structured according to a unique mathematical framework, represented by Table 1 or variants. A similar framework can be used as well for completely different mathematical situations, for example sets of rectangles of equal area. In this case, column I contains the widths of the rectangles, column II the reciprocals of the widths, column III the lengths, and column IV the equal areas (see examples in Proust 2007: 202205).
§3.7. Organization of our calculations. In our commentary of YBC 4698, in particular in the reconstruction of the calculations expected for solving the problems (§6), we attempt, as much as possible, to follow the mathematical framework attested in OB mathematical texts, especially in school texts. This implies the following chart to represent the entire mathematical framework:

The metrological data provided by the statements of the problems are transformed into SPVN according to the metrological tables. Thus, the reader is invited to refer to these metrological tables throughout the reading of this article (see §8.3).

The calculations in SPVN are represented in tabular form, where each column represents an operation (for example, column II represents reciprocals of data of column I, or column III represents the multiplication by a coefficient of data of column II, and so on).

The results of the calculations are transformed into measures according to the metrological tables, with a mental control of the orders of magnitude.
It is important to keep in mind that this framework includes both the use of metrological tables and tabular presentation of numbers in SPVN. When relevant from a mathematical point of view, we use the threestep chart above in our reconstructions of the possible calculations performed by ancient scribes (see conventions below in §3.8). We prefer to use charts attested in Old Babylonian sources instead of modern formalism because we are convinced that the organization of calculations made by modern historians has a substantial impact on the understanding of ancient texts. This impact is as important (and even more so) as the choice of notations in the transliterations, or the terminology used to translate the ancient terms.
§3.8. Conventions. To be clear in the tabular presentation, to distinguish the data provided explicitly or implicitly by the original text from the results of our calculations, we note in bold the former and in plain the latter. Correspondences between metrological data and abstract numbers as provided by metrological tables are represented by an arrow (→). For example: 1 gin_{2} → 1, or 1 še → 20. An outline of the metrological tables can be found in §8.3, and the complete set of metrological tables attested in Nippur is provided in Proust 2009.
§4. Transliteration and translation
obverse i

1

1

še ana 1(aš) še gur

(When the principal in) grain (is) as much as 1 gur of grain,


2

1(barig) še ana maš_{2} šum_{2}

1 barig of grain as the interest I give.


3

še u_{3} maš_{2} ennam

The grain and the interest are how much?



2

4

še ana 1(aš) še gur

(When the principal in) grain (is) as much as 1 gur of grain,


5

1(barig) 4(ban_{2}) ana maš_{2} šum_{2}

1 barig 4 ban_{2} as the interest I give.


6

še u_{3} maš_{2} ennam

The grain and the interest are how much?



3

7

3 sila_{3}ta i_{3} sag

(Rates inkind are) 3 sila_{3} of first quality oil per (gin_{2})


8

1(ban_{2}) 2 sila_{3}ta i_{3}geš

(and) 1 ban_{2} 2 sila_{3} of common oil per (gin_{2}).


9

1 gin_{2} ku_{3}babbar šum_{2}

1 gin_{2} of silver I gave.


10

i_{3}geš u_{3} i_{3} sag

Common oil and first quality oil


11

ib_{2}sa_{2}ma sa_{10}

I made equal and I bought.



4

12

1(geš_{2}) 3(u) DUG anbar

60+30 DUG of iron


13

9^{?} DUG ku_{3}sig_{17}

9 (×60^{?}) DUG of gold,


14

1 mana ku_{3}babbar šum_{2}

1 mana silver I gave.


15

anbar u_{3} ku_{3}sig_{17}

The iron and gold


16

1 gin_{2}ma sa_{10}

(is) 1 gin_{2} and I bought.



5

17

^{1}/_{2} mana ku_{3}babbar šum_{2}

^{1}/_{2} mana of silver I gave.


18

1(aš) gurta sa_{10}

1 gur per (gin_{2}) I bought.



obverse ii

6

1

3(u) še gur

30 gur grain


2

1(aš) še gurta sa_{10}ma

1 gur of grain per (gin_{2}) I bought,


3

4(barig) šeta bur_{2}ra

4 barig of grain per (gin_{2}) I sold.


4

ku_{3} diri ennam

The silver profit is how much?


5

7 ^{1}/_{2} gin_{2} ku_{3}babbar diri

7 ^{1}/_{2} gin_{2} of silver is the profit.



7

6

sag ku_{3}bi ennam

The initial price is how much?



8

7

1(aš) gur i_{3}geš

1 gur of common oil.


8

1(ban_{2})ta sa_{10}ma

1 ban_{2} per (gin_{2}) I bought and,


9

8 sila_{3}ta bur_{2}ra

8 sila_{3} per (gin_{2}) I sold.


10

ku_{3} diri ennam

The silver profit is how much?


11

7 ^{1}/_{2} gin_{2} ku_{3} diri

7 ^{1}/_{2} gin_{2} is the silver profit.



9

12

1(aš) gur i_{3}geš

1 gur of common oil.


13

ina sa_{10} 1^{!} gin_{2}

When the purchase is 1^{!} (text: 2) gin_{2},


14

2 sila_{3} šuš_{4}

2 sila_{3} I cut.


15

7 ^{1}/_{2} gin_{2} ku_{3} diri

7 ^{1}/_{2} gin_{2} is the profit.


16

ennam sa_{10}ma

How much did I buy?


17

ennam bur_{2}ra

How much did I sell?


18

1(ban_{2}) sa_{10}ma

1 ban_{2} I bought and


19

8 sila_{3} bur_{2}ra

8 sila_{3} I sold.



reverse i

10

1

1(aš) gur i_{3}geš

1 gur of common oil.


2

9 sila_{3}ta sa_{10}ma

9 sila_{3} per (gin_{2}) I bought,


3

7 ^{1}/_{2} sila_{3} bur_{2}ra

7 ^{1}/_{2} sila_{3} per (gin_{2}) I sold.


4

ku_{3} diri ennam

The profit is how much?


5

6 ^{2}/_{3} gin_{2} ku_{3} diri

6 ^{2}/_{3} gin_{2} is the silver profit.



11

6

1(aš) gur i_{3}geš

1 gur of common oil.


7

ina sa_{10} 1 gin_{2} 1 ^{1}/_{2} sila_{3} šuš_{4}

When the purchase is 1 gin_{2}, 1 ^{1}/_{2} sila_{3} I cut.


8

6 ^{2}/_{3} gin_{2} ku_{3} diri

6 ^{2}/_{3} gin_{2} is the silver profit.


9

ennam sa_{10}ma ennam bur_{2}ra

How much did I buy? How much did I sell?


10

9 sila_{3} sa_{10}ma 7 ^{1}/_{2} sila_{3} bur_{2}ra

9 sila_{3} I bought, and 7 ^{1}/_{2} sila_{3} is sold.



12

11

7 mana u_{3} 11 mana siki geš^{?}

(Per) 7 mana and 11 mana of ... wool


12

1 gin_{2} ku_{3} šum_{2} ib_{2}sa_{2}ma sa_{10}ma

1 gin_{2} silver I paid. I made equal and I bought.


13

4.16.40 sa_{10}

4.16.40 I bought.



13

14

7 sila_{3}ta i_{3}geš

Per 7 sila_{3} of common oil


15

1(ban_{2}) 2(diš) sila_{3}ta i_{3}šaḫ_{2}

per 1 ban_{2} 2 sila_{3} of lard,


16

1(diš) gin_{2} šum_{2} ib_{2}sa_{2}ma sa_{10} 2(ban_{2}) 3 ^{1}/_{3} sila_{3}

1 gin_{2} I gave. I made equal and I bought: 2 ban_{2} 3 ^{1}/_{3} sila_{3}.



14

17

ganba ana 1 2 3 4 5

(When) rates (inkind are) as much as 1 2 3 4 5


18

6 7 8 9 ganba

6 7 8 9, the rate (in grain)


19

1(barig) še šum_{2} še he_{2}e_{3}

1 barig I give. Let the grain rise


20

u_{3} he_{2}e_{11}ma

or fall so that


21

ganba ib_{2}sa_{2}

the rates (inkind) are equal.



reverse ii

15

1

ganba 3 ku_{6}a 5 sila_{3}

Rate (inkind) for 3 fish, 5 sila_{3}


2

5 ku_{6}a ku_{6} [...]

for 5 fish, fish ...


3

še gargarma 4(aš) 1(barig) 4(ban_{2}) 5 (2^{?}) <sila_{3}>

The grain I added: 4 (gur) 1 barig 4 ban_{2} 5 (2^{?}) (sila_{3} gur)


4

ku_{6}a gargarma ku_{6}

The fish I added. Let the fish


5

še ḫe_{2}e_{3} u_{3} ḫe_{2}e_{11}ma

and the grain rise or fall


6

ku_{6}a ib_{2}sa_{2}

so that the fish are equal.



16

7

mala ganba ḫia nagga

As much as the rates (inkind) of the lead


8

ku_{3} i_{3}^{?}la_{2}ma

silver I weighed and


9

nagga sa_{10}

lead I bought.


10

ku_{3} u_{3} nagga gargarma

The silver and the lead I added:


11

7 mana ku_{3} u_{3} nagga 7 mana.

The silver and the lead


12

ennam

are how much?



17

13

na_{4} šutiama

Stones I received and


14

kila_{2}bi nuzu

their weight I don’t know.


15

6ta sa_{10}

6 (stones) per (gin_{2}) I bought.


16

6ta ku_{3}sig_{17} garra

6 gold inlaid (stones) per (gin_{2} I bought).


17

ku_{3}sig_{17} garra

Gold inlaid (stones),


18

ana 6ta sa_{10}

as much as 6 (stones) per (gin_{2}) I bought.


19

na_{4} ku_{3}babbar ennam

The stone, the silver how much


20

gargarma ^{1}/_{2} mana 1 ^{1}/_{2} gin_{2}

did I add^{?} ^{1}/_{2} mana 1 ^{1}/_{2} gin_{2}


21

x ma na^{?} gargarma

... I added and


22

1 mana 3 gin_{2}

1 mana 3 gin_{2}.



bottom edge


1

(erasure) dub 3kamma

Tablet number 3.

§5. Philological notes
#3

In obv. i 3 and passim, we read i_{3}, following ThureauDangin (1937b: 89) and Friberg (2005: 61), but Neugebauer reads NA_{4} under Goetze’s suggestion (see Archives AaboeBritton in §9 below). In obv. i 11 and passim, we read sa_{10} following ThureauDangin (1937b: 89) and Friberg (2005: 61) who chooses the nominalized form šam_{2}, but Neugebauer reads ANŠE.

#4

In obv. i 1213, we read “DUG,” following Neugebauer (MKT 3, 42), which is confirmed by our collations as well as a reading performed by Cavigneaux. However, Friberg (2005: 61) reads “bi,” thus, his interpretation is completely different (ibid., 6768 and §6.4 below). We may understand this situation as one dealing with objects, the nature of which we cannot currently identify, made of iron and gold. Since iron was a very rare and precious metal in the Old Babylonian period, it is surprising that the proportion of iron and gold is 90 to 9. However, it is possible that the proportion is 90 to 9×60 (or 1 to 6). Thus 9 may represent 9 sixties instead of 9 units (according to another suggestion of Cavigneaux). In this case, we should restore “9 <šuši>.” Another possibility would be that “DUG” refers to a container, perhaps alluding to leftovers from the metallurgical process. For a textual example of this latter use of a metal, see YOS 2, 112 11, anna ḫiimmi u_{3} šaaktišu, which we translate “tin sweepings and its powder.”

#5

In obv. i 18, we read “1(aš) gurta,” following Neugebauer (MKT 3, 42), but Friberg (2005: 61) reads “^{1}/_{2} gin_{2}ma.”

#6

In obv. ii 3 and passim, we read “bur_{2}” following Friberg (2005: 61) and Cavigneaux (pers. com.), but Neugebauer (MKT 3, 42) reads “bala.”

#9

In obv. ii 14 and passim, we read the sign “ŠUM” following Neugebauer (MKT 3, 42), which we transliterate as “šuš_{4},” to cut, because of the parallel with kašāṭum, to cut, found in an analogous text, TMS 13. However Friberg (2005: 61) reads “si_{3}.”

#12

In rev. i 11, we read “siki geš^{?}” (wool of a certain kind) where Neugebauer reads (MKT 3, 42) “RU …,” and Friberg (2005: 61) “ruqa.”

#13

In rev. i 14, Friberg and Neugebauer read 6 sila_{3}. However, we distinguished clearly the number “7” on the tablet. In line 15, the last sign is probably sag, as in other similar contexts, but this sign is not clear; Friberg reads “šaḫ.”
In rev. i 16, the signs 2 ban_{2} 3 ^{1}/_{3} sila_{3} are visible on the right edge of the tablet, but they do not appear in Neugebauer’s copy, nor in Friberg’s transliteration (Friberg 2005: 61). According to the Archive AaboeBritton now kept at ISAW (see §9), Neugebauer used the photos of the obverse and reverse of the tablet, but did not have the photos of the edges, while Friberg’s analysis of YBC 4698 was based solely on Neugebauer’s hand copy.

#14

The reading of this statement by Friberg is quite far from ours (and from Neugebauer’s): in rev. i 18, Friberg reads “šuši” instead of “ganba”; line 19 he reads “1 še si_{3} še šam_{2}ma” instead of Neugebauer’s “1 gun_{2} sum še ib_{2}sa_{2} du_{6}.” Following Neugebauer, however, he reads “GIŠ” instead of “DU” in line 20.
In the beginning of rev. i 19, the reading 1(barig) še is probable, but not certain. Neugebauer (MKT 3, 42) transliterates “3(gur)(?),” which seems quite improbable, and Friberg (2005: 61) “1 (gur) še,” which is possible, but not consistent with the other data of the statement.

#15

In “ḫe_{2}e_{3} u_{3} ḫe_{2}e_{11}” (rev. ii 5), the reading of e_{11} (DU_{6}.DU) is uncertain. There is the possibility of reading this e_{3} (UD.DU), though taken with problem 14 ll. 1920 it is clear that e_{11} was intended by the scribe. Note that the ma placed in line 6 belongs in fact to line 5 that lacked space for it.
In rev. ii 4, we believe that the last sign is clearly ‘ku_{6},’ while Friberg (pers. comm.) suggests another possibility: “this should be a number, possibly 2 ner = 20.00.” We exclude this possibility because the graphy of the sign here is the same as in ll. 1 and 2 of this section, and the number “2(geš’u)” should have a slightly different graphic form (wedges and Winkelhaken more neatly separated—see for example HS 1703 rev. v). Moreover, we do not expect a number noted in system S here.

#17

Rev. ii 1617, we translate ‘ku_{3}sig_{17} garra’ as ‘gold inlaid,’ following Cavigneaux’s suggestion.

§6. Comments
#1

The statement gives the interest to be paid for the loan of a given amount of grain that is, 1 barig per gur. The question asks principal and interest, or, perhaps, the total principal + interest. It seems that some information concerning the principal is missing, so we cannot solve the problem. Perhaps the missing data were given in previous tablets of the series. Or, as another hypothesis, suggested by Neugebauer (MKT 3 43), the question concerns the interest rate, that is, the interest by unit of grain (1 sila_{3}). In this case, the calculation would be quite simple.


The interest rate is thus ^{1}/_{5}, that is, 12, which corresponds to 12 gin_{2} per sila_{3}.
Note that the interest rate of ^{1}/_{5} (or 20%) is the standard value for annual silver loans. The customary value for grain is ^{1}/_{3} per year though texts do vary. See, for instance, YOS 14, 178: 2, a loan where the interest rate is stipulated at 1 barig per gur, the rate presented here.
Interestingly, Friberg (personal communication) suggests an even simpler solution, that is, 1 gur is the actual principal, 1 barig is the actual interest, and the question is “what is the principal plus (u_{3}) the interest.” The answer should be 1 gur 1 barig.

#2

This statement is identical to the previous one, with an interest of 1 barig 4 ban_{2} per gur. The calculation of the interest rate would be:


1 gur

→ 5


1(barig) 4(ban_{2})

→ 1.40


The interest rate is thus ^{1.40}/_{5}, that is, 1.40 × 12 = 20, which corresponds to 20 gin_{2} per sila_{3}. Note that this corresponds to a rate of ^{1}/_{3}, which is the customary rate for a grain loan as stated above.

#3

The rate inkind of first quality oil is given as 3 sila_{3} (this means that the value of 3 sila_{3} of first quality oil is 1 gin_{2} of silver), and the rate inkind of common oil is given as 1 ban_{2} 2 sila_{3} (the value of 1 ban_{2} 2 sila_{3} of common oil is 1 gin_{2} of silver). The same quantity of both oils is bought. However, this common quantity is not specified, and there is no question, nor answer, so that we may consider the following hypothesis:
The total value in silver of the oils bought is 1 gin_{2} (line 9). The problem can be solved by using the chart as explained in §3: the metrological data are converted into SPVN using metrological tables, the numbers in SPVN are displayed in tabular format and finally, the result is converted into metrological notation by means of a metrological table. Note that in Table 2 and thereafter, bold numbers correspond to data provided by the text, either as SPVN, or as metrological notation, while the use of metrological tables is represented by an arrow (→). Here, metrological tables provide:


3 sila_{3}

→ 3


1(ban_{2}) 2 sila_{3}

→ 12


1 gin_{2}

→ 1


The reader has to calculate the value of each kind of oil (column III of Table 2), and/or the common quantity (column IV). To solve the problem, we first note that the rate insilver (column II) is the reciprocal of the rate inkind (column I) and fill in accordingly. The total of items of column II is 25, and the total of the items of column III is 1. Thus, the coefficient of column III is 2.24 (reciprocal of 25) and column III is easy to fill. We can then fill in column IV which is the product of data of columns I and III, that is, the coefficient 2.24. According to metrological tables and a mental control of the orders of magnitude, the results correspond to the following weights and capacity:


48

→ ^{2}/_{3} gin_{2} 24 še


12

→ ^{1}/_{6} gin_{2} 6 še


2.24

→ 2 ^{1}/_{3} sila_{3} 4 gin_{2}


For 2 ^{1}/_{3} sila 4 gin_{2} of premium oil, ^{2}/_{3} gin_{2} 24 še silver is given and for the same amount of common oil, ^{1}/_{6} gin_{2} 6 še silver is given. This seems to be the solution espoused by Friberg (2005: 6061).


Col.

I

II

III

IV




Reciprocal of I

II × 2.24

I × III



Rate inkind

Rate insilver

Value insilver

Value inkind


First quality oil

3

20

48

2.24


Common oil

12

5

12

2.24



Total


25

1



Table 2: calculations for solving #3

#4

Statement #4 seems to be similar to #3, except for two key points: the suffix –ta is not used nor does it state that the two goods “I made equal and I bought” but instructs that the two goods (here iron and gold) “is 1 gin_{2} and I bought,” in the same position. Like in #3, the transaction is expressed by the verbs ‘sum’ (to give) and ‘sa_{10}’ (to buy). However, this transaction is not completely clear to us. Only an attempt of interpretation is offered here.


Lines 1213 seem to indicate that we deal with two lots of objects (DUG): 90 (60+30) iron objects and 9 gold objects. Line 14 states “1 mana silver I gave,” thus we understand that 1 mana is the total value insilver of the two lots, like in #3. Lines 1516 refer to ‘1 gin_{2}’ in relation to iron and gold. The nature of this relation is not clear. 1 gin_{2} can hardly be the total weight of the two lots, or its total value insilver (a weight of about 8 g for 99 objects is hard to imagine; and a value insilver of 8 g for these 99 precious objects is even more unrealistic). We can guess that 1 gin_{2} represents the weight of each object. Even so, this is not made explicit in the text. If this suggestion is correct, the total weight of iron bought is 1 . mana (90 times 1 gin_{2}) and the total weight of gold bought is 9 gin (9 times 1 gin_{2}).
The goal of the problem may be the value in silver of the 90 iron objects and of the 9 gold objects. Thus we need to know the rate insilver of both metals. It then seems that data needed to evaluate rates is missing. This data could have been well known by the reader of the text, or it may have been provided in previous tablets of the series. Note that, if we suppose that the rate insilver of iron is 8, a widely attested value (see below), then the rate insilver of gold is 5.20 (because we know that the total value of iron plus gold is 1 mana). 5.20 is a realistic value for the rate insilver of gold. Moreover, the rates 8 and 5.20 are regular numbers, as well as their sum (13.20), and the sum of their reciprocals 7.30 and 11.15 (18.45).
The understanding of the problem by Friberg (2005, 67), is different. For him, “iron and gold are 90 and 9 times more valuable than silver, and if 1 shekel of iron and gold together is bought for 1 mina of silver, what are then the amount of iron and gold, respectively?” In modern language, this should lead to a system of two linear equations. The solution should be 37.46.40 and 22.13.20 (;37 46 40 and ;22 13 20 with Friberg’s notations). We do not believe that the first two lines of #4 state that “iron and gold are 90 and 9 times more valuable than silver,” because the syntax of the cuneiform text should be different. We should have: “1(geš_{2}) 3(u) gin_{2}ta anbar / 9(diš) gin_{2}ta ku_{3}sig_{17}.” Moreover, the values would be completely unrealistic. According to Cécile Michel (pers. comm.), “In the Old Babylonian period, the ratio iron : silver is 1:8 in Southern Mesopotamia; 1:12 in Mari, and 1:40 in Aššur. The ration gold : silver is between 1:3 and 1:6 in Southern Mesopotamia, between 1:4 and 1:6 in Mari, and between 1:4 and 1:8 in Aššur.”

#5

Problem #5 seems to be a variant of #4. According to a system of notation widely used in series texts, only the modified information is noted in the variant, the unchanged information being omitted. The complete statement of #5 would be the following (the information given in #4 but omitted in #5 is noted between triangular brackets):


<1(geš_{2}) 30 DUG anbar>


<9(geš_{2}^{?}) DUG ku_{3}sig_{17}>


^{1}/_{2} mana ku_{3}babbar sum


<anbar u_{3} ku_{2}sig_{17}>


1(aš) gurta sa_{10}


The variant should be:
The total value insilver of the two lots is ^{1}/_{2} mana instead of 1 mana
The weight in gin_{2} is replaced by an equivalent value ingrain (which means that the weight of iron objects is not the same as the weight of gold objects). The interpretation raises the same difficulties already witnessed in #4.

#6

Neugebauer interpreted the statement as asking for a profit made in purchasing 30 gur of grain, knowing expected losses (5 barig), and actual losses (4 barig) (MKT 3, 44).
The situation is much simpler if we consider that the transaction consists in buying and selling 30 gur of grain, and that the question asks for the profit in silver. This is also the understanding of Friberg (2005: 217), against Neugebauer. The text states that if 1 gur of grain is bought for a given price (sa_{10}), 4 barig of this grain is sold (bur_{2}) for the same price. Data consistency requires that the purchase price of 1 gur of grain is 1 gin_{2} of silver, but this value is not provided in the statement. Indeed, since the market prices are usually given as capacity by gin_{2} (rate inkind) it is not necessary to precise “per 1 gin_{2},” which is implicit. This interpretation assumes that bur_{2} here has the sense ‘to sell,’ that is, the contrary of to buy (reverse operation, see §2.3).
The calculations may run as follows. First, the metrological data are transformed into SPVN using the metrological table of capacities:


30 gur

→ 2.30


1 gur

→ 5


4(barig)

→ 4


Then, the calculations are performed with the aid of tabular format indicated in table 3.
Finally, the profit is 7.30, the difference between the sale and purchase prices (column III). The metrological table of weights provides the metrological expression of the profit:


7.30

→ 7 ^{1}/_{2} gin_{2}


The profit is 7 ^{1}/_{2} gin_{2}, as stated in the answer (obv. col. ii, line 5).
Note that the profit (7.30) may be calculated in two ways:


a) Multiplying the difference of col. II (3) by the coefficient 2.30


b) Calculating the difference of purchase and selling prices in col. III.


Col.

I

II

III

IV




Reciprocal of I

II × 2.30

I × III



Rate inkind

Rate insilver

Price insilver

Value inkind


Purchase

5

12

30

2.30


Sale

4

15

37.30

2.30



difference


3

7.30



Table 3: calculations for solving #6

#7

This section seems to be an additional question related to the statement of #6. If we consider that the situation is the same as in #6, the additional question probably asks the purchase price of the 30 gur of grain. This is an indication that, in #6, the profit is calculated by method a). The purchase price of the 30 gur is obtained by multiplying 12 by 2.30 (see Table 3). The result is 30, which corresponds to a purchase price of 30 gin_{2}.

#8

This problem is similar to #6, but the good purchased is 1 gur of oil instead of 30 gur of grain. As in the previous section, the metrological data are transformed into SPVN using the metrological table of capacities:


1 gur

→ 5


1(ban_{2})

→ 10


8 sila_{3}

→ 8


Then, the calculations are performed with the aid of tabular format indicated in table 4.
Finally, the profit is 7.30, the difference of the sale and purchase prices (column III). The metrological table of weights provides the metrological expression of the profit:


7.30

→ 7 ^{1}/_{2} gin_{2}


The profit is 7 ^{1}/_{2} gin_{2}, as stated in the answer (obv. ii 11).


Col.

I

II

III

IV


Reciprocal of I

II × 5

I × III


Rate inkind

Rate insilver

Price insilver

Value inkind


Purchase

10

6

30

5


Sale

8

7.30

37.30

5



difference


1.30

7.30



Table 4: calculations for solving #8

#9

A new operation appears in line 14: 2 sila_{3} are “cut” (šuš_{4}) from the good sold. This translation of ‘šuš_{4}’ is suggested by TMS 13, which contains a similar problem with a complete resolution. The statement TMS 13 (lines 14) runs as follows, according to our collation of the tablet, which corresponds to Friberg’s transliteration (2010: 154), except in line 2, where Friberg left out the sequence ‘i_{3}geš’.


2(gur) 2(barig) 5(ban_{2}) i_{3}geš sa_{10} ina sa_{10} 1 gin_{2} ku_{3}babbar

2 gur 2 barig 5 ban_{2} of common oil I bought. When the purchase (costs) 1 gin_{2} silver (of oil),


4 sila_{3}taam_{3} i_{3}geš akši_{2}iṭma

4 sila_{3} of common oil I cut and


^{2}/_{3} mana 20 še ku_{3}babbar nemela

^{2}/_{3} mana 20 še silver of profit I see.


amuur_{2} ki maṣi ašaam u_{3} ki maṣi apšuur_{2}

How much did I buy? How much did I sell?


Parallel terms in TMS 13 and YBC 4698, resp.:


kašāṭum

šuš_{4}

to cut


šâmum, sa_{10}

sa_{10}

to buy


pašārum

bur_{2}

to sell


‘šuš_{4}’ is parallel to the Akkadian ‘kašāṭum’ used in TMS 13. The 2 sila_{3} “cut” represents the difference between the purchase and the selling rates inkind.


Col.

I

II

III

IV


Reciprocal of I

II × 5

I × III


Rate inkind

Rate insilver

Price insilver

Value inkind


Purchase

10 (a)

6 (a')


5


Sale

8 (b)

7.30 (b')


5



difference

2

1.30

7.30



Table 5: calculations for solving #9


Thus, we can understand the statement of YBC 4698 #9 as a reverse problem of the previous one: the difference between the purchase and the selling rates inkind being 2 sila_{3}, and the profit for 1 gur being 7 ^{1}/_{2} gin_{2}, find the purchase and the selling rates inkind. However, this interpretation assumes that the purchase rate is given per 1 gin_{2}, not per 2 gin_{2} as noted in the tablet (obv. col. i, line 13)


1 gur

→ 5


2 sila_{3}

→ 2


7 ^{1}/_{2} gin_{2}

→ 7.30


Since the difference of price insilver is 7.30 (col. III of table 5), the difference of rates in silver is ^{7.30}/_{5}, that is, 1.30 (col. II). The problem consists, then, of finding two numbers, a and b, from their difference (2) and the difference of their reciprocals a' and b' (1.30). In modern language, this problem may be represented by the system of equations:


This leads to the problem of finding two numbers knowing their difference (2) and their product (^{2}/_{1.30}, that is, 1.20) (for the method of resolution of this quadratic problem, see the explanation of TMS 13 in Høyrup 2002: 206209). The solution is a = 10 and b = 8.


10

→ 1(ban_{2})


8

→ 8 sila_{3}


The purchase and the selling rates inkind are thus 1 ban_{2} and 8 sila_{3}. This solution corresponds to the answer given in the text (obv. col. ii, lines 1819).


#10

This problem is similar to #8, with other purchase and sale rates. The purchase and the selling rates inkind are 9 sila_{3} and 7 ^{1}/_{2} sila_{3}. The metrological data are (in SPVN):


1 gur

→ 5


9 sila_{3}

→ 9


7 ^{1}/_{2} sila_{3}

→ 7.30


See table 6 for calculations. The result 6.40 provided by col. III, corresponds to 6 ^{2}/_{3} gin:


6.40

→ 6 ^{2}/_{3} gin_{2}


The profit is 6 ^{2}/_{3} gin_{2}, as stated in the answer (rev. i 5).


Col.

I

II

III

IV


Reciprocal of I

II × 5

I × III


Rate inkind

Rate insilver

Price insilver

Value inkind


Purchase

9

6.40

33.20

5


Sale

7.30

8

40

5



difference


1.20

6.40



Table 6: calculations for solving #10

#11

As in the case of #9, the problem #11 presents the reverse of the previous one.


1 gur

→ 5


1 ^{1}/_{2} sila_{3}

→ 1.30


6 ^{2}/_{3} sila_{3}

→ 6.40


Since the difference of prices insilver is 6.40 (col. III of table 7), the difference of rates insilver is ^{6.40}/_{5}, that is, 1.20 (col. II). The problem consists then, of finding two numbers, a and b, from their difference (1.30) and the differences of their reciprocals a' and b' (1.20).
In modern language, this problem may be represented by the system of equations:


a – b

= 1.30


b' – a'

= 1.20


The solution of this quadratic problem is a = 9 and b = 7.30.


9

→ 9 sila_{3}


7.30

→ 7 ^{1}/_{2} sila_{3}


The purchase and the selling rates inkind are thus 9 sila_{3} and 7 ^{1}/_{2} sila_{3}. This solution corresponds to the answer given in the text (rev. i 10).


Col.

I

II

III

IV


Reciprocal of I

II × 5

I × III


Rate inkind

Rate insilver

Price insilver

Value inkind


Purchase

9 (a)

6.40 (a')


5


Sale

7.30 (b)

8 (b')


5



difference

1.30

1.20

6.40



Table 7: calculations for solving #11

#12

Problem 12 provides the rate inkind of two types of wool, 7 mana and 11 mana respectively, as well as their total value in silver, 1 gin_{2}. There is no question, but it seems that the problem is to find the equal quantities of wool 1 and wool 2, and that the answer is given in the last line: this quantity corresponds to 4.16.40.
In this problem, the rates inkind correspond to nonregular numbers (7 and 11), which means that the reciprocal cannot be found. One finds the same situation in VAT 7530, as well as in several “combined market rate exercises” (see Friberg 2007: 162, 165). These texts suggest that, as the reciprocal of the rates insilver cannot be found, column II does not provide the rates insilver, but instead the product of the rates insilver by 7 ×11.


7 mana

→ 7


11 mana

→ 11


1 gin_{2}

→ 1


Column II of table 8 contains the product of the reciprocal of 7 by 7×11, which is 11, and the product of the reciprocal of 11 by 7×11, which is 7. The total of column II is 18. The number 18 is a false value which must be compared to the actual total value in silver of 1 gin_{2} (total column III) in order to produce a coefficient of 3.20 (the reciprocal of 18). This coefficient is necessary to multiply the rates in column II in order to produce column III. Thus we see:


11× 3.20

= 36.40


7 × 3.20

= 23.20


The next step is to multiply the rates in column I by the values in silver in column III to produce the values in kind of column IV, 4.16.40 in both cases. Thus we have filled in the table and obtained the required equal quantities of wool 1 and wool 2:


4.16.40

→ 4 mana 16 ^{2}/_{3} gin_{2}


The number 4.16.40 corresponds to the answer given in line 13. Curiously, the answer is expressed in place value notation and not, as usual, in metrological notation.


Col.

I

II

III

IV


Reciprocal of I ×7×11

II × 3.20

I × III


Rate inkind

Rate insilver×7×11

Value insilver

Value inkind (equal)


Wool 1

7

11

36.40

4.16.40


Wool 2

11

7

23.20

4.16.40



Total


18

1



Table 8: sketch of calculations for solving #12

#13

The rates inkind of two types of oil are given (7 mana per gin_{2} and 1 ban_{2} 2 sila_{3} per gin_{2}) that correspond to the following SVPN:


7 mana

→ 7


1(ban_{2}) 2 sila_{3}

→ 12


1 gin_{2}

→ 1


The same quantity of each type of oil is bought for the price of 1 gin_{2} of silver (total of column III of table 9). There is no question, but we may suppose that the reader was expected to calculate the price of each kind of oil (column III), and/or the common quantity (column IV).
The rate inkind of common oil is 7, a nonregular number, thus column II is replaced with the products of the rates insilver by 7.
The total of items of column II is 36, and the total of the items of col. III is 1. Thus, the coefficient of col. III is 1.40 (reciprocal of 36). The rest of the table is then easy to fill. The value inkind of common oil is 11.40, of lard is 11.40, thus the total is 23.20, which corresponds to 2 ban_{2} 3 ^{1}/_{3} sila_{3}, the answer provided on the edge of the tablet (which does not appear in Neugebauer’s hand copy – see note on #13 in §5).


Col.

I

II

III

IV


Reciprocal of I ×7

II × 1.40

I × III


Rate inkind

Rate insilver ×7

Value insilver

Value inkind (equal)


Common oil

7

1

1.40

11.40


Lard

12

35

58.20

11.40



Total


36

1

23.20



Table 9: calculations for solving #13

#14

Statement #14 displays similarities to N 3914 discussed in (Friberg 2007, 163165) and to VAT 7530 #5 (obv. 1721) discussed in (Friberg 2007, 166). The purpose of this problem is to find each quantity that corresponds to each given rate inkind, from 1 to 9 in this problem, that will add up to a total amount paid, probably stipulated as “1(barig) še” in this problem. One of the rates in problem 14 is the number 7, a nonregular number in the sexagesimal system as in #12 and 13. Unlike the problems discussed in Friberg, problem 14 added an extra step: the scribe had to round in order to find the answer. Also, unlike both N 3914 and VAT 7530 § 5, problem 14 uses grain to evaluate the unnamed goods instead of silver, a significant deviation from the prior problems in this series.
There are nine sorts of goods, for which the rates inkind are respectively 1 (unit), 2 (units), ..., 9 (units) (quantities which equivalent value ingrain is 1 sila_{3}).
The value inkind of the goods (column IV of table 10) must be a multiple of 7, the unique nonregular rate inkind of the problem. Thus column II is replaced with the products of the rates ingrain by 7. Following the idea of Friberg (cf. N 3914 in Friberg 2007: 163165), we designate these products as “false value ingrain.” The coefficient providing the actual value is calculated using the information given in line 19 of the text: the total value in grain of the nine goods bought is 1 barig (corresponding to 1). The total false value ingrain is 19.48.10 (approximately 20). The total value of the purchase to be found must be 1 barig (1). The coefficient is approximately the reciprocal of 20, that is, 3. Multiplying the values of column II by 3 gives the actual values ingrain of the nine goods (column III). The value inkind is the false quantity, 7, multiplied by the coefficient, 3, that is, 21. It is also the product of column I, the rates inkind, by column III, the values ingrain.
Since #14 exhibits some similarities with VAT 7530 obv. 1721, this text deserves to be quoted (following Neugebauer, MKT 1, 288):


1 mana taam_{3} 2 mana [3 ma]˹na˺ 4 mana, 5 mana

Per 1 mana, 2 mana, 3 mana, 4 ma˹na˺ [5 mana]


6 mana 7 mana 8 mana 9 mana 10 ˹mana˺

6 mana, 7 mana, 8 mana, 9 mana, 10 mana,


10 gin_{2} igi 4gal_{2} u_{3} šizaaat^{[14]} še ku_{3}babbar

10 ^{1}/_{4} gin_{2} and ^{1}/_{3} še silver


ku_{3}babbar lili liridama

Let the silver rise and fall,


ganba liimtahira

so that the rate inkind is equal.


I

II

III

IV



(reciprocal of I × 7)

(II × 3)

(I × III)


Rate inkind

False value ingrain

Value ingrain

Value inkind (equal)


1

7

21

21


2

3.30

10.30

21


3

2.20

7

21


4

1.45

5.15

21


5

1.24

4.12

21


6

1.10

3.30

21


7

1

3

21


8

52.30

2.37 30

21


9

46.40

2.20

21



Total

19.48.10

59.24.30

3.9



Rounded

20

1


Difference

11.50

35.30


Error

1%



Table 10: calculations for solving #14

#15

Problem 15 provides both a connection with problem 14 and a significant departure from the previous sections. It is connected to problem 14 in that it continues the use of value ingrain rather than value insilver. However, a significant departure is seen in that the exchange rate is no longer stated as X inkind quantity per 1 gin_{2} of silver, but X inkind quantity per Y sila_{3} grain. The value inkind is a number of fish. Thus we see two rates in problem 15: 3 ku_{6}a 5 sila_{3} “for 3 fish, 5 sila_{3},” and 5 ku_{6}a ku_{6} […] “for 5 fish ….” The exchange rate is a ratio of ^{3}/_{5} (36) and 5/x respectively. These ratios can be easily converted into the same formula as in the previous problems. The data are converted in SPVN as follows:


5 sila_{3}

→ 5


4(aš) 1(barig) 4(ban_{2}) 5 (sila_{3}^{?})

→ 21.45


Table 11 provides the following interpretation. Column I is the rate inkind, ^{3}/_{5} or 36. Column II is then the reciprocal, that is, ^{5}/_{3} or 1.40. It is interesting to see that the goal of the problem is the same as in #14, to find the values ingrain and inkind. However, to underline that there is a significant difference in the ratio, the ta suffix is not employed, and the problem states in lines 56, ku_{6} še ḫe_{2}e_{3} u_{3} ḫe_{2}e_{11} ku_{6}a ib_{2}sa_{2}ma, “Let the fish and the grain rise or fall (so that) the fish are equal.” Unfortunately the second rate is broken and so we are unable to solve this problem completely. Interesting is the use of ganba to describe this problem in line 1. One would expect a different term if the use of a different form or ratio defined by both the inkind and ingrain rate is employed. However, this use makes sense when it is understood that the problem is a rate inkind exercise, that is, that the use of the rate inkind must be found and employed to find the answer. If this is true, then the use of ganba as described in §2.4 is justified. This is, in the end, a rate inkind problem and ganba’s use here informs us on how the author of this text expected to deal with an odd exchange rate.
Further, we see a similar use of ganba in economic texts. As an example, we turn again to RA 15, 191 (mentioned above §2.4), this time to lines 13:


8 gu_{2} siki sagga_{2}

8 gu_{2} select white wool,


ganba 1 gu_{2}e 7 ^{1}/_{2}

rate inkind to 1 gu_{2} 7 ^{1}/_{2} gin_{2},


ku_{3}bi 1 mana

its value 1 mana.


Note that in this example the explicit lack of the ta suffix which is present in lines 1618 of the same document to describe another rate. The difference between RA 15, 191, and our text would be the directive/ locative e in RA 15, 191, which is not explicitly mentioned in YBC 4698.


Col.

I

II

III

IV


Rate inkind

Rate ingrain

Value ingrain

Value inkind


Fish

1 36 (^{3}/_{5})

1.40 (^{5}/_{3})


Fish 2

? (5/x)

? (x/5)



Total


21.45



Table 11: calculations for solving #15

#16

This statement was correctly read and translated by ThureauDangin (1937b: 8990; our rendering of the French):
As much as the price of lead I paid (literally weighed) some silver, I bought some lead, I added silver and lead: 7 mana. The silver and lead are what?
As noted by ThureauDangin, the market rate of lead is missing, and the problem cannot be solved. However, it seems to us that arithmetical arguments actually demand that the rate inkind of lead be 7.
Indeed, lines 1011 seem to indicate that the weight of lead bought and the weight of silver used for buying the lead are added and that the total weight of metal is 7 mana (total value inkind, corresponding to 7—see table 12, col. IV). As it is stated that “As much as the rates inkind of the lead silver I weighed and lead I bought,” the weight of lead must be equal to the weight of silver, that is, 3.30 (col. IV). Thus, the weights of both metals are 3.30. The goal of the problem is probably to find the value in silver of lead (col. III). Of course, the rate inkind of silver is 1 and the value insilver of silver is the same as the value inkind of silver, that is, 3.30. For the lead, it seems that the lead’s rate is missing, as noted by ThureauDangin. However, we can rely on the fact that 3.30 = 7×30, thus the factor 7 appears in columns I, II and III. Therefore, the rate inkind of lead must be 7. Since 7 is not regular, column II cannot provide reciprocals of rates inkind, but instead provides 7 times the reciprocals of rates inkind. The coefficient providing values insilver (col. III) from rates insilver is 3.30, thus the coefficient which produces col. III from col. II is 30 (because col. II is 7 time the rates insilver). The table can be filled, and the problem can be solved.


The value insilver of lead is ^{1}/_{2} mana.
Note the use of the verb la_{2} to mark the means of payment. The actor weighed out silver against the lead, and literally found the exchange ratio in the purchase.


Col.

I

II

III

IV


Reciprocal of I × 7

II × 30

I × III


Rate inkind

Rate insilver × 7

Value insilver

Value inkind


Lead

7

1

30

3.30


Silver

1

7

3.30

3.30



Total


8

4

7



Table 12: calculations for solving #16

#17

Even if the situation described by this statement is not completely clear to us, it seems quite sure that:


1)

We are dealing with two kinds of stones: common stones and gold inlaid (ku_{3}sig_{17} garra) stones. 6 stones of each kind are bought. As the value of 6 common stones is 1 unit (probably 1 gin_{2} of silver, as usual), and the value of 6 gold inlaid stones is the same, the weight of one common stone is not the same as the weight of one gold inlaid stone.


2)

The question is probably to find the weight of each kind of stones, that is, the rate inkind of 6 common stones and of 6 inlaid stones, as well as the corresponding rates insilver (line 19).


3)

Lines 17 and 18 seem to describe the process of making equal the quantities of the two kinds of stones. Thus, the weight of common stone is ^{1}/_{2} mana 1 ^{1}/_{2} gin_{2} (31.30), as well as the weight of inlaid stones; the total weight is 1 mana 3 gin_{2} (1.3), as stated in line 22.


Col.

I

II

III

IV


Reciprocal of I ×7

II × 4.30

I × III


Rate inkind

Rate Insilver ×7

Value insilver

Value inkind


(weight of stones per 1 gin)


(price of the stones)

(equal weights of stones)


Common stones

6 a

7 × 10 × a'

5.15 a'

31.30


Gold inlaid stones

6 b

7 × 10 × b'

5.15 b'

31.30



Total


1

1.3



Table 13: sketch of calculations for solving #17


Col.

I

II

III

IV


Reciprocal of I ×7

II × 4.30

I × III


Rate inkind

Rate Insilver ×7

Value insilver

Value inkind


Common stones

6 × 21

3.20

15

31.30


Gold inlaid stones

6 × 7

10

45

31.30



Total


1

1.3



Table 14: possible sketch of calculations for solving #17


Now, if we observe that 31.30 is 7×4.30, we guess that the factor 7 appears in rates inkind, and that the situation is similar to #12. Thus, column II of Table 13 contains the products of reciprocals of column I by 7 (in the table, a is the weight of one common stone, and a' the reciprocal of a; b is the weight of one inlaid stone, and b' the reciprocal of b). We can now calculate the factor k providing column III from column II. Indeed, since IV is I × III, we have:


31.30

= 6 a × 7 × 10 × a' × k


The values of a and b can be calculated, assuming that the total of column III is 1, as usual:


5.15 (a' + b')

= 1


7 × 45 (^{1}/_{a} + ^{1}/_{b})

= 1


(a + ^{b})/_{ab}

= ^{1}/_{7} × 1.20


This means that a or b is a multiple of 7. Of course, an infinity of solutions is possible. Say, for simplicity, that b = 7; thus a = 21.
The starting point of this analysis of the problem is the answer (the equal weights of the two kinds of stones is ^{1}/_{2} mana 1 ^{1}/_{2} gin_{2}), that is, we filled in Table 13 from col. IV to col. I. Some data seem missing in order to fill the table from col. I to col. IV.
However, suppose that it was already stated in a previous tablet of this series that inlaid stone has three times more value than common stone: if the weight of one inlaid stone is n, then, the weight of one common stone is 3n. Moreover, suppose that, in order to solve the problem, the column II provides the false value equal to “Reciprocal of I ×n.” In this way the problem can be solved. A crucial test, to evaluate this hypothesis, should be to decipher the first signs of line 21, which remain unclear for us.

§7. Conclusion
§7.1. Some of the problems of the text remain unclear or uncertain. However, the improvement of the understanding of the text we tried to offer, compared to Neugebauer, ThureauDangin and Friberg’s previous publications, lies in the meaning of the whole text. This set of 17 problems presents a strong consistency, and most of the statements appear as variations of a basic mathematical sketch. We tried to underline this single mathematical framework by referring systematically to the same chart, represented by conversions and a table of data, which emerges from school exercises (§3.2 and §3.3). In diverse situations, direct and reverse problems are built by suggesting different paths in filling the corresponding table of data.
§7.2. Some of the uncertainties of interpretation originate in our lack of pieces of information. This probably results from the fact that this tablet is just one tablet in a series (the third one), and that relevant information may have been provided in the first two tablets of the series. This detail underlines the importance of considering texts as wholes, when possible. It must be noted that some of the statements have parallels in the known corpus of mathematical procedure texts and school exercises. This means that the author of the tablet reused old mathematical material. But, unlike catalogue texts, the list of statements noted on YBC 4698 doesn’t seem to be a compilation gathering statements from different sources, but rather a systematic elaboration of new material from old material. This is a typical feature of series texts (Proust 2009b).
§7.3. Another striking feature of this text is the way in which Akkadian expressions used elsewhere in mathematical texts are translated word for word into a quite artificial Sumerian language. The trace of Akkadian expressions is particularly clear in problems 14 and 15 (še ḫe_{2}e_{3} u_{3} ḫe_{2}e_{11}ma ganba ib_{2}sa_{2}). The use of Sumerograms such as bur_{2}, e_{3} and e_{11} seems to be specific to this text, since only the Akkadian counterparts are attested in other mathematical texts. These linguistic features probably reflect the habits of a highly erudite milieu.
§8. Indices
§8.1. Glossary
ana

as much as

anbar

iron

bur_{2}

to sell

DUG

object (unclear meaning)

e_{3}

to rise

e_{11}

to fall

ennam

how much?

ganba

rate (inkind or insilver)

gargar

to add

i_{3}geš

common oil

i_{3} sag

first quality oil

i_{3}šah_{2}

lard

ib_{2}sa_{2}

to make equal

kila_{2}

weight, to weigh

ku_{3}babbar

silver

ku_{3}babbar diri

silver profit

ku_{3} diri

silver profit (abbreviation)

ku_{3}sig_{17}

gold

ku_{3}sig_{17} garra

inlaid gold

ku_{3}sum

to pay

ku_{3} la_{2}

to weigh silver, to pay

ku_{6}

fish

la_{2}

to weigh

maš_{2}

interest

na_{4}

stone

nagga

lead

sa_{10}

v. to buy, to make equivalent; n. purchase, equivalent

siki

wool

šum_{2}

to give

šutia

received

šuš_{4}

to cut

zu

to know

§8.2. Metrological systems
Units of capacities (1 sila_{3} ≈ 1 liter)
gur

←×5←

barig

←×6←

ban_{2}

←×10←

sila_{3}

sila_{3}

←×60←

gin_{2}

←×180←

še

Units of weight (1 mana ≈ 500 g)
gu_{2}

←×60←

mana

←×60←

gin_{2}

←×180←

še

§8.3. Metrological tables (outline)
Capacities
1 še

20

1 gin_{2}

1

1 sila_{3}

1

1(ban_{2})

10

1(barig)

1

1 gur

5

Weights
1 še

20

1 gin_{2}

1

1 mana

1

1 gu_{2}

1

The complete OB metrological tables according to Nippur sources can be found in Proust 2009a: §8.
§9. Neugebauer archives
A copy of the folder “YBC 4698” from the AaboeBritton Archives is provided in figure 1. These archives, which contain the documents used by Neugebauer for the publication of MKT and MCT, are kept at the Institute for the Study of the Ancient World, New York University. We thank Alexander Jones for scanning these documents for us and allowing us to present them here.
The folder contains
1) the transliteration of the reverse of YBC 4698 by Neugebauer, with annotations by Albrecht Goetze
2) a postcard sent by Goetze to Neugebauer on April 17, 1935
3) the photographs used by Neugebauer to publish the text in MKT 3, 4245
These photographs are not included in MKT. ThureauDangin used copies of the same photographic negative, sent to him by the curator, Ferris J. Stephens. More detail on AaboeBritton Archives and on the way in which Neugebauer and ThureauDangin worked with photographs can be found in (Proust & Rougemont forthcoming).
Figure 1: AaboeBritton Archives, folder “YBC 4698” (courtesy of ISAW/NYU)
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Abbreviations

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MKT 1 = Neugebauer 1935

MKT 3 = Neugebauer 1937

TMB = ThureauDangin 1938

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